does anyone want to help me with Calc2???

[Dexter]

please?????


i know someone out there must love math , at 12:30 AM....

its trigonometric intergrals and trig substitutions


god im so ******.

 

[Captain KRM P5]

your precious carputer can't save you now

i've got faith in you bryan. i've also got a stuck sneeze. damn.

 

[mp3moose]

Sorry man,
I'd help you out but I just failed a calc exam yesterday. Praying is your best option.

Moose

 

[alexlitov]

What is the problem??

 

[Dexter]

 /      
 |  (sin 2x)^5(cos 2x)dx
 /

i tried to make that as understandable as possible. that is the integrate sign there on the left.

what ive done so far...is factored out a sin

 /      
 |  (sin 2x)^4(cos 2x)(sin 2x)dx
 /

and now by what the book says, im supposed to save that sin i just factored out. okay, done. and then im supposed to convert the OTHER sin to cos. how??

 

[alexlitov]

AS far as I remember, I don't think you did it right.... Now do the same iwth sin.

 

[Dexter]

holy ****...i think im onto something...

 /      
 |  (sin 2x)^2 (sin 2x)^2 (cos 2x)(sin 2x)dx
 /

(sin x)^2 +(cos x)^2 = 1

but that doesnt help me does it??

 

[Dexter]

i need to get those Sin2x's to cosines so i can use the Power Rule and 'U' substitution, where u = sin 2x ?

 

[DaleGribble]

You're on the right track. If you let u=sin(2x), then it's derivative, du=2cos(2x). Then your original integral becomes:
/
2| u^5 du
/
because you can pull constants out of integrals.
So that looks like a form that's familiar.
Then your solution to that is 2*(1/6)u^6 = (1/12)u^6
Then you resub with u=sin(2x) to get your final answer as
(1/12)(sin(2x))^6...I think

 

[boostisgood]

I am just ******* lost here. Best i got was algerbra 2

 

[RyanJayG]

I hated Calc 2.... thank God its in the distant past... 7 years ago

 

[CruzinAltitude]

I just failed a calc exam yesterday. Praying is your best option.

Truer words have never been spoken.

 

[jred321]

You're on the right track. If you let u=sin(2x), then it's derivative, du=2cos(2x). Then your original integral becomes:
/
2| u^5 du
/
because you can pull constants out of integrals.
So that looks like a form that's familiar.
Then your solution to that is 2*(1/6)u^6 = (1/12)u^6
Then you resub with u=sin(2x) to get your final answer as
(1/12)(sin(2x))^6...I think

this guy knows what he's talkin about. if i need to do integrals, i love my ti-89

 

[traitorhound]

man im so happy im done with calc. .. .pre-med only requires 2 semesters of math. . .i took calc 1 and got a b. . ..and now im in stat (boring but easy)

 

[Dexter]

You're on the right track. If you let u=sin(2x), then it's derivative, du=2cos(2x). Then your original integral becomes:
/
2| u^5 du
/
because you can pull constants out of integrals.
So that looks like a form that's familiar.
Then your solution to that is 2*(1/6)u^6 = (1/12)u^6
Then you resub with u=sin(2x) to get your final answer as
(1/12)(sin(2x))^6...I think

dude, thanks alot for the explaination. i ironically enough have to run to class now, but yeah it makes sense...kinda..im sure when i read it thru it will. thanks agian

 

[katsmp3]

God Bless the TI-92

 

[tonkabui]

it should be 1/2 the integral u^5 du. when you sub u=sin2x, your du=2cos2x dx. isolate your dx to replace in your original equation and you get du/(2cos2x). take out the constant, then cancel cos2x on top and bottom. then the rest is elementary.

 

[RyanJayG]

TI-92's rule... hell, they do the calc for you

 

[neit_jnf]

You've all committed too many SINS!!! HAHAHAHA

 

[2K3 MSP]

My brain hurts just trying to look at that stuff. I took Algebra 2 for like two days, then dropped it. I couldn't even imagine trying that crap you guys are talking about.